# A poll of 234 students at a university reveals that 72 are taking a lab science…   A poll of 234 students at a university reveals that 72 are taking a lab science course, and 48 are members of the Honors College, while 18 are taking a lab science and are members of the Honors College. Let L = the event that a student is taking a lab science, and H=the event that a student is a member of the Honors College. Complete parts (a) through (e) below. OA. OB. OC. OD 72 1848 3018) 54 54 18 30 48 1872 96 1321 1321 96. b. A student is randomly chosen. Find P(L) and P(L H’) and explain what each number represents. First determine the formula to use to find P(L). P(L) = P(L) = (Simplify your answer.) Determine the formula to use to find PL H’). PKL 0H) = POLO H’) = (Simplify your answer.) Explain what P(L) and P( LH’) represent. Choose the correct answer below. O A. P(L) is the probability a student is taking a lab science. P(LnH’) is the probability a student is taking a lab science and is not a member of the Honors College. O B. P(L) is the probability a student is taking a lab science. P(LnH’) is the probability a student is taking a lab science or is not a member of the Honors College. OC. P(L) is the probability a student is not a member of the Honors College. P(L H’) is the probability a student is taking a lab science and is not a member of the Honors College. OD. P(L) is the probability a student is not a member of the Honors College. P(L H’) is the probability a student is taking a lab science or is not a member of the Honors College.
c. A student is randomly chosen. Find P(H) and P(H n L’) and explain what each number represents. P(H)= (Simplify your answer.) P(H OL’)=(Simplify your answer.) Explain what P(H) and P(H L’) represent. Choose the correct answer below. O A. P(H) is the probability a student is a member of the Honors College. P(H O L’) is the probability a student is a member of the Honors College and is not taking a lab science. OB. P(H) is the probability a student is not taking a lab science. P(H OL’) is the probability a student is a member of the Honors College and is not taking a lab science. OC. P(H) is the probability a student is not taking a lab science. (HOL’) is the probability a student is a member of the Honors College or is not taking a lab science. OD. P(H) is the probability a student is a member of the Honors College. P(H O L’) is the probability a student is a member of the Honors College or is not taking a lab science. d. A student is randomly chosen. Find P( LH) and P(( LH)’) and explain what each number represents. P( LH)= (Simplify your answer.) P(LH)’) = (Simplify your answer.) Explain what P( LH) and P(LH)) represent. Choose the correct answer below. O A. P(LNH) is the probability a student is taking a lab science or is a member of the Honors College. P((LOH)) is the probability a student is not taking a lab science and is not a member of the Honors College. O B. P( LH) is the probability a student is taking a lab science and is a member of the Honors College. P(CLH)’) is the probability a student is not taking a lab science and is not a member of the Honors College. OC. PLN H) is the probability a student is taking a lab science and is a member of the Honors College. P(LH)’) is the probability a student is not taking a lab science or is not a member of the Honors College OD. P(LOH) is the probability a student is taking a lab science or is a member of the Honors College. P(LOH)) is the probability a student is not taking a lab science or is not a member of the Honors College.
e. Find the odds against each event in parts (c-d) occurring, First write an expression for the odds against H. Select all that apply. A. P(H’):P(H) OC. P(H): (1 – P(L)) E. 1- P(H): P(H) IB. (1-P(H’)): P(H) OD. P(H):P(H’) OF. P(H): (1 – P(H’)) The odds against H occurring, in lowest terms, are (Type whole numbers.) Next find the odds against Hol’ occurring. First write an expression for these odds. Select all that apply. A. (1 – P(HNL’)): P(HOL) OC. (1-P((HOL’)’)):P(HOL’) E. P(CHOL’)’) :P(HOL’) B. P(HOL’):P((H’OL)’) OD. P(HOL’):(1-P(HOL’)) OF. P(HOL’):(1-P((HOL)))) The odds against H n l’occurring, in lowest terms, are (Type whole numbers.) Next find the odds against L H occurring. First write an expression for these odds. Select all that apply. A. P(LH)’) :P( LH) OC. (1-P(( LH))) :PLOH) E. P( LH): (1 – P( LH)) B. PLOH):P(( LH)) OD. PLOH): (1 – P(( LH)’)) F. (1 – P( LH)):P( LH) The odds against L H occurring, in lowest terms, are (Type whole numbers.) The odds against ( LH)’, in lowest terms, are: (Type whole numbers.)